Truly Tabular RDF/Info
Property columns
#
rank of the property in order of the percentage of instances where at lest one values is available for the property
%
The percentage of instances where at least one value is available for the property
pareto
The Pareto level according to the Pareto principle 80:20 (1 out of 5) as a logarithmic scale to the basis 5..
level | ratio | 1 out of |
---|---|---|
1 | 80:20 | 5 |
2 | 96:4 | 25 |
3 | 99.2:0.8 | 125 |
4 | 99.84:0.16 | 625 |
5 | 99.97:0.03 | 3125 |
6 | 99.994:0.006 | 15625 |
7 | 99.9987:0.0013 | 78125 |
8 | 99.99974:0.00026 | 390625 |
9 | 99.99995:0.00005 | 1953125 |
property
A Wikidata Property e.g. P31/instance of
propertyId
The property Identifier for a Property e.g. P31 for P31/instance of
Statistics
1
maxf
nt
nt%
?f
?ex
try it! link to examples for "non-tabular" entries. E.g. for the property "manufacturer" of the class "beer" the query
# This query was generated by Truly Tabular
# Count all Q44:beer items
# with the given manufacturer(P176) https://www.wikidata.org/wiki/Property:P176
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX schema: <http://schema.org/>
PREFIX wd: <http://www.wikidata.org/entity/>
PREFIX wdt: <http://www.wikidata.org/prop/direct/>
PREFIX wikibase: <http://wikiba.se/ontology#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
SELECT ?item ?itemLabel (COUNT (?value) AS ?count)
WHERE
{
# instance of beer
?item wdt:P31 wd:Q44.
?item rdfs:label ?itemLabel.
FILTER (LANG(?itemLabel) = "en").
# manufacturer
?item wdt:P176 ?value.
} GROUP BY ?item ?itemLabel
HAVING (COUNT (?value) > 1)
ORDER BY DESC(?count) try it
try it! will be generated which reveals that there are two kinds of beers that have two manufacturers: Žatecký Gus which is manufactured by Carlsberg Ukraine and Baltika Breweries and Balatoni Világos which is manufactured by
✔
Aggregates
count
apply SPARQL
COUNT()
aggregate
min
apply SPARQL
MIN()
aggregate
max
apply SPARQL
MAX()
aggregate
avg
apply SPARQL
AVG()
aggregate
sample
apply SPARQL
SAMPLE()
aggregate
list
apply
GROUP_CONCAT()
aggregate to avoid multiple solutions for the same instance
ignore
Ignore SPARQL solutions that have multiple values for the given property by using a
HAVING COUNT<=1
aggregate condition in the generated query
label
Show the label of the property result in the generated SPARQL query.
select
If a property is selected it will be included in the generated SPARQL query